8a^2-41a+50=0

Solution for 8a^2-41a+50=0 equation:

8a^2-41a+50=0

a = 8; b = -41; c = +50;
Δ = b2-4ac
Δ = -412-4·8·50
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-9}{2*8}=\frac{32}{16}
=2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+9}{2*8}=\frac{50}{16}
=3+1/8
$